[amp_mcq option1=”indeterminate” option2=”0″ option3=”1″ option4=”\\[\\infty \\]” correct=”option3″]<\/p>\n
The correct answer is $\\boxed{\\text{indeterminate}}$.<\/p>\n
The limit $\\lim_{x\\to 0}\\frac{\\sin x}{x}$ is indeterminate because as $x$ approaches 0, the ratio $\\frac{\\sin x}{x}$ approaches 1. However, the limit does not actually equal 1, because $\\sin x$ is not always equal to $x$ when $x$ is close to 0. For example, when $x=0.1$, $\\sin x=0.09959304$, and when $x=-0.1$, $\\sin x=-0.09959304$. Therefore, the limit $\\lim_{x\\to 0}\\frac{\\sin x}{x}$ does not exist.<\/p>\n
Option A is incorrect because the limit is not equal to 0. Option B is incorrect because the limit is not equal to 1. Option C is incorrect because the limit is not equal to $\\infty$.<\/p>\n","protected":false},"excerpt":{"rendered":"
[amp_mcq option1=”indeterminate” option2=”0″ option3=”1″ option4=”\\[\\infty \\]” correct=”option3″]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[690],"tags":[],"class_list":["post-20178","post","type-post","status-publish","format-standard","hentry","category-calculus","no-featured-image-padding"],"yoast_head":"\n