[amp_mcq option1=”4″ option2=”6″ option3=”8″ option4=”12″ correct=”option3″]<\/p>\n
A matrix is singular if its determinant is zero. The determinant of a 3×3 matrix can be calculated using the formula below:<\/p>\n
$$\\det \\left[ {\\begin{array}{{20}{c}} a&b&c \\ d&e&f \\ g&h&i \\end{array}} \\right] = (-1)^{a+b+c} \\left| \\begin{array}{<\/em>{20}{c}} a&c \\ e&i \\end{array} \\right| + b \\left| \\begin{array}{{20}{c}} b&f \\ d&h \\end{array} \\right| + c \\left| \\begin{array}{<\/em>{20}{c}} c&d \\ e&g \\end{array} \\right|$$<\/p>\n In this case, the matrix is:<\/p>\n $$\\left[ {\\begin{array}{*{20}{c}} 8&{\\text{x}}&0 \\ 4&0&2 \\ {12}&6&0 \\end{array}} \\right]$$<\/p>\n Therefore, the determinant is:<\/p>\n $$\\det \\left[ {\\begin{array}{{20}{c}} 8&{\\text{x}}&0 \\ 4&0&2 \\ {12}&6&0 \\end{array}} \\right] = (-1)^{8+0+0} \\left| \\begin{array}{<\/em>{20}{c}} 8&0 \\ 12&0 \\end{array} \\right| + 0 \\left| \\begin{array}{{20}{c}} 8&2 \\ 12&6 \\end{array} \\right| + 0 \\left| \\begin{array}{<\/em>{20}{c}} 8&2 \\ 4&6 \\end{array} \\right| = 0$$<\/p>\n The determinant is zero when $x=0$. Therefore, the matrix becomes singular when $x=0$.<\/p>\n","protected":false},"excerpt":{"rendered":" [amp_mcq option1=”4″ option2=”6″ option3=”8″ option4=”12″ correct=”option3″]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[489],"tags":[],"class_list":["post-20012","post","type-post","status-publish","format-standard","hentry","category-linear-algebra","no-featured-image-padding"],"yoast_head":"\n