{"id":19993,"date":"2024-04-15T05:46:57","date_gmt":"2024-04-15T05:46:57","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=19993"},"modified":"2024-04-15T05:46:57","modified_gmt":"2024-04-15T05:46:57","slug":"one-of-the-eigen-vectors-of-the-matrix-texta-left-beginarray20c-22-13-endarray-right-is-a-left-beginarray20c-2-1-endarray","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/one-of-the-eigen-vectors-of-the-matrix-texta-left-beginarray20c-22-13-endarray-right-is-a-left-beginarray20c-2-1-endarray\/","title":{"rendered":"One of the eigen vectors of the matrix \\[{\\text{A}} = \\left[ {\\begin{array}{*{20}{c}} 2&#038;2 \\\\ 1&#038;3 \\end{array}} \\right]\\] is A. \\[\\left\\{ {\\begin{array}{*{20}{c}} 2 \\\\ { &#8211; 1} \\end{array}} \\right\\}\\] B. \\[\\left\\{ {\\begin{array}{*{20}{c}} 2 \\\\ 1 \\end{array}} \\right\\}\\] C. \\[\\left\\{ {\\begin{array}{*{20}{c}} 4 \\\\ 1 \\end{array}} \\right\\}\\] D. \\[\\left\\{ {\\begin{array}{*{20}{c}} 1 \\\\ { &#8211; 1} \\end{array}} \\right\\}\\]"},"content":{"rendered":"<p>[amp_mcq option1=&#8221;\\[\\left\\{ {\\begin{array}{*{20}{c}} 2 \\\\ { &#8211; 1} \\end{array}} \\right\\}\\]&#8221; option2=&#8221;\\[\\left\\{ {\\begin{array}{*{20}{c}} 2 \\\\ 1 \\end{array}} \\right\\}\\]&#8221; option3=&#8221;\\[\\left\\{ {\\begin{array}{*{20}{c}} 4 \\\\ 1 \\end{array}} \\right\\}\\]&#8221; option4=&#8221;\\[\\left\\{ {\\begin{array}{*{20}{c}} 1 \\\\ { &#8211; 1} \\end{array}} \\right\\}\\]&#8221; correct=&#8221;option3&#8243;]<!--more--><\/p>\n<p>The correct answer is $\\boxed{\\left\\{ {\\begin{array}{*{20}{c}} 2 \\ { &#8211; 1} \\end{array}} \\right\\}}$.<\/p>\n<p>To find the eigenvalues and eigenvectors of a matrix, we can use the following formula:<\/p>\n<p>$$\\lambda v = A v$$<\/p>\n<p>where $\\lambda$ is the eigenvalue, $v$ is the eigenvector, and $A$ is the matrix.<\/p>\n<p>In this case, we have:<\/p>\n<p>$$\\begin{align<em>}<br \/>\n\\lambda v &amp;= A v \\<br \/>\n\\lambda \\left( \\begin{array}{c} 2 \\ -1 \\end{array} \\right) &amp;= \\left( \\begin{array}{cc} 2 &amp; 2 \\ 1 &amp; 3 \\end{array} \\right) \\left( \\begin{array}{c} 2 \\ -1 \\end{array} \\right) \\<br \/>\n\\lambda \\left( \\begin{array}{c} 2 \\ -1 \\end{array} \\right) &amp;= \\left( \\begin{array}{c} 4 \\ 3 \\end{array} \\right) \\<br \/>\n\\lambda &amp;= 4 \\<br \/>\n\\end{align<\/em>}$$<\/p>\n<p>Therefore, one of the eigenvalues of the matrix is $\\lambda = 4$.<\/p>\n<p>To find the corresponding eigenvector, we can solve the following equation:<\/p>\n<p>$$\\begin{align<em>}<br \/>\nAv &amp;= \\lambda v \\<br \/>\n\\left( \\begin{array}{cc} 2 &amp; 2 \\ 1 &amp; 3 \\end{array} \\right) \\left( \\begin{array}{c} x \\ y \\end{array} \\right) &amp;= \\left( \\begin{array}{c} 4 \\ 3 \\end{array} \\right) \\<br \/>\n2x + 2y &amp;= 4 \\<br \/>\nx + 3y &amp;= 3 \\<br \/>\n\\end{align<\/em>}$$<\/p>\n<p>Solving this system of equations, we get:<\/p>\n<p>$$x = 2, \\quad y = -1$$<\/p>\n<p>Therefore, one of the eigenvectors of the matrix is $\\boxed{\\left\\{ {\\begin{array}{*{20}{c}} 2 \\ { &#8211; 1} \\end{array}} \\right\\}}$.<\/p>\n<p>The other eigenvalue and eigenvector of the matrix can be found similarly.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>[amp_mcq option1=&#8221;\\[\\left\\{ {\\begin{array}{*{20}{c}} 2 \\\\ { &#8211; 1} \\end{array}} \\right\\}\\]&#8221; option2=&#8221;\\[\\left\\{ {\\begin{array}{*{20}{c}} 2 \\\\ 1 \\end{array}} \\right\\}\\]&#8221; option3=&#8221;\\[\\left\\{ {\\begin{array}{*{20}{c}} 4 \\\\ 1 \\end{array}} \\right\\}\\]&#8221; option4=&#8221;\\[\\left\\{ {\\begin{array}{*{20}{c}} 1 \\\\ { &#8211; 1} \\end{array}} \\right\\}\\]&#8221; correct=&#8221;option3&#8243;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[489],"tags":[],"class_list":["post-19993","post","type-post","status-publish","format-standard","hentry","category-linear-algebra","no-featured-image-padding"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>One of the eigen vectors of the matrix \\[{\\text{A}} = \\left[ {\\begin{array}{*{20}{c}} 2&amp;2 \\\\ 1&amp;3 \\end{array}} \\right]\\] is A. \\[\\left\\{ {\\begin{array}{*{20}{c}} 2 \\\\ { - 1} \\end{array}} \\right\\}\\] B. \\[\\left\\{ {\\begin{array}{*{20}{c}} 2 \\\\ 1 \\end{array}} \\right\\}\\] C. \\[\\left\\{ {\\begin{array}{*{20}{c}} 4 \\\\ 1 \\end{array}} \\right\\}\\] D. \\[\\left\\{ {\\begin{array}{*{20}{c}} 1 \\\\ { - 1} \\end{array}} \\right\\}\\]<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/one-of-the-eigen-vectors-of-the-matrix-texta-left-beginarray20c-22-13-endarray-right-is-a-left-beginarray20c-2-1-endarray\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"One of the eigen vectors of the matrix \\[{\\text{A}} = \\left[ {\\begin{array}{*{20}{c}} 2&amp;2 \\\\ 1&amp;3 \\end{array}} \\right]\\] is A. \\[\\left\\{ {\\begin{array}{*{20}{c}} 2 \\\\ { - 1} \\end{array}} \\right\\}\\] B. \\[\\left\\{ {\\begin{array}{*{20}{c}} 2 \\\\ 1 \\end{array}} \\right\\}\\] C. \\[\\left\\{ {\\begin{array}{*{20}{c}} 4 \\\\ 1 \\end{array}} \\right\\}\\] D. \\[\\left\\{ {\\begin{array}{*{20}{c}} 1 \\\\ { - 1} \\end{array}} \\right\\}\\]\" \/>\n<meta property=\"og:description\" content=\"[amp_mcq option1=&#8221;[left{ {begin{array}{*{20}{c}} 2 \\ { &#8211; 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