{"id":19925,"date":"2024-04-15T05:46:04","date_gmt":"2024-04-15T05:46:04","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=19925"},"modified":"2024-04-15T05:46:04","modified_gmt":"2024-04-15T05:46:04","slug":"in-allene-hybridization-of-the-central-and-terminal-carbons-respectively-are-a-sp2-and-sp2-b-sp2-and-sp3-c-sp-and-sp2-d-sp-and-sp3","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/in-allene-hybridization-of-the-central-and-terminal-carbons-respectively-are-a-sp2-and-sp2-b-sp2-and-sp3-c-sp-and-sp2-d-sp-and-sp3\/","title":{"rendered":"In allene, hybridization of the central and terminal carbons respectively, are A. sp2 and sp2 B. sp2 and sp3 C. sp and sp2 D. sp and sp3"},"content":{"rendered":"<p>\r\n    <!-- Check if it's an AMP page -->\r\n            <!-- Non-AMP version -->\r\n        <div class=\"mcq-container\" data-quiz-id=\"quizState_6a9a086398d08\">\r\n                                            <div class=\"option\" data-option-key=\"option1\" data-is-correct=\"false\">\r\n                    sp2 and sp2                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option2\" data-is-correct=\"false\">\r\n                    sp2 and sp3                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option3\" data-is-correct=\"true\">\r\n                    sp and sp2                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option4\" data-is-correct=\"false\">\r\n                    sp and sp3                <\/div>\r\n                            \r\n            <!-- Feedback messages for non-AMP -->\r\n            <div class=\"feedback\" data-feedback=\"wrong\">Answer is Right!<\/div>\r\n            <div class=\"feedback\" data-feedback=\"right\">Answer is Wrong!<\/div>\r\n        <\/div>\r\n\r\n        <script>\r\n        document.addEventListener('DOMContentLoaded', function () {\r\n            var containers = document.querySelectorAll('.mcq-container');\r\n\r\n            containers.forEach(function(container) {\r\n                var options = container.querySelectorAll('.option');\r\n                var feedbackSelect = container.querySelector('[data-feedback=\"select\"]');\r\n                var feedbackWrong = container.querySelector('[data-feedback=\"wrong\"]');\r\n                var feedbackRight = container.querySelector('[data-feedback=\"right\"]');\r\n\r\n                options.forEach(function(option) {\r\n                    option.addEventListener('click', function() {\r\n                        var selectedOption = option.getAttribute('data-option-key');\r\n                        var isCorrect = option.getAttribute('data-is-correct') === 'true';\r\n\r\n                        \/\/ Remove previous selections\r\n                        options.forEach(function(opt) {\r\n                            opt.classList.remove('correct', 'incorrect');\r\n                        });\r\n\r\n                        \/\/ Add the correct\/incorrect class\r\n                        if (isCorrect) {\r\n                            option.classList.add('correct');\r\n                            feedbackRight.hidden = false;\r\n                            feedbackWrong.hidden = true;\r\n                        } else {\r\n                            option.classList.add('incorrect');\r\n                            feedbackRight.hidden = true;\r\n                            feedbackWrong.hidden = false;\r\n                        }\r\n\r\n                        \/\/ Hide select feedback\r\n                        feedbackSelect.hidden = true;\r\n                    });\r\n                });\r\n            });\r\n        });\r\n        <\/script>\r\n    \r\n    <!--more--><\/p>\n<p>The correct answer is: C. sp and sp2<\/p>\n<p>The central carbon in allene is bonded to two other carbons and two hydrogens. The terminal carbons are bonded to one other carbon and two hydrogens.<\/p>\n<p>In order to minimize electron repulsion, the central carbon will hybridize its s and p orbitals to form three sp hybridized orbitals. These orbitals are arranged in a trigonal planar geometry with 120\u00c2\u00b0 angles between them. The two p orbitals that are not hybridized are perpendicular to the plane of the sp hybridized orbitals.<\/p>\n<p>The terminal carbons will hybridize their s and p orbitals to form two sp2 hybridized orbitals. These orbitals are arranged in a trigonal planar geometry with 120\u00c2\u00b0 angles between them. <div class=\"youtube-subscribe-container\">\r\n        <a href=\"https:\/\/www.youtube.com\/channel\/UCNHT8lW-JmLC68rjBfZhdkg?sub_confirmation=1\" target=\"_blank\" class=\"youtube-subscribe-button\">\r\n            <span class=\"youtube-icon\">\r\n                <svg xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 576 512\">\r\n                    <path d=\"M549.7 <div class=\"telegram-channel-container\">\r\n        <a href=\"https:\/\/t.me\/pscnotes2025\" target=\"_blank\" class=\"telegram-channel-button\">\r\n            <span class=\"telegram-icon\">\r\n                <svg xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 496 512\">\r\n                    <path fill=\"white\" d=\"M248,8C111,8,0,119,0,256s111,248,248,248s248-111,248-248S385,8,248,8z M362,177L320,367c-3,14-10,18-20,14l-56-41l-27,26 c-3,3-5,5-10,5l4-63L323,196c5-5-1-7-8-3l-98,62l-42-13c-9-3-10-9,2-14l162-63C351,160,365,164,362,177z\"\/>\r\n                <\/svg>\r\n            <\/span>\r\n            Join Our Telegram Channel\r\n        <\/a>\r\n    <\/div> 124.1c-6.3-23.7-24.8-42.3-48.3-48.6C458.8 64 288 64 288 64S117.2 64 74.6 75.5c-23.5 6.3-42 24.9-48.3 48.6-11.4 42.9-11.4 132.3-11.4 132.3s0 89.4 11.4 132.3c6.3 23.7 24.8 41.5 48.3 47.8C117.2 448 288 448 288 448s170.8 0 213.4-11.5c23.5-6.3 42-24.2 48.3-47.8 11.4-42.9 11.4-132.3 11.4-132.3s0-89.4-11.4-132.3zm-317.5 213.5V175.2l142.7 81.2-142.7 81.2z\"\/>\r\n                <\/svg>\r\n            <\/span>\r\n            Subscribe on YouTube\r\n        <\/a>\r\n    <\/div> The remaining p orbital is perpendicular to the plane of the sp2 hybridized orbitals.<\/p>\n<p>The following diagram shows the hybridization of the carbon atoms in allene:<\/p>\n<p>The sp hybridized orbitals on the central carbon are used to form sigma bonds with the two terminal carbons. The p orbitals on the central carbon are used to form pi bonds with the two terminal carbons. The sp2 hybridized orbitals on the terminal carbons are used to form sigma bonds with the central carbon and hydrogen atoms. The remaining p orbital on the terminal carbon is used to form a pi bond with the central carbon.<\/p>\n<p>I hope this explanation is helpful!<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Subscribe on YouTube<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[688],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>In allene, hybridization of the central and terminal carbons respectively, are A. sp2 and sp2 B. sp2 and sp3 C. sp and sp2 D. sp and sp3<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" 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