[amp_mcq option1=”II > I > III” option2=”II > III > I” option3=”III > I > II” option4=”I > II > III” correct=”option1″]<\/p>\n
The correct answer is: A. II > I > III<\/strong><\/p>\n The reactivity of a compound towards electrophiles depends on the electron density in the compound. The more electron-rich the compound, the more reactive it will be towards electrophiles.<\/p>\n In the given compounds, the electron density is highest in compound II, followed by compound I, and lowest in compound III. This is because compound II has a phenyl group, which is an electron-donating group. The phenyl group donates electrons to the ring, making the ring more electron-rich. Compound I also has a phenyl group, but it is not as electron-donating as the phenyl group in compound II. This is because the phenyl group in compound I is attached to a carbonyl group, which is an electron-withdrawing group. The carbonyl group withdraws electrons from the ring, making the ring less electron-rich. Compound III does not have any electron-donating groups, and it has an electron-withdrawing group (the carbonyl group). This makes compound III the least electron-rich of the three compounds.<\/p>\n Therefore, the decreasing order of the reactivity of the following compounds towards electrophiles is:<\/p>\n II > I > III<\/p>\n","protected":false},"excerpt":{"rendered":" [amp_mcq option1=”II > I > III” option2=”II > III > I” option3=”III > I > II” option4=”I > II > III” correct=”option1″]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[688],"tags":[],"class_list":["post-19915","post","type-post","status-publish","format-standard","hentry","category-basics-of-organic-reaction-mechanism","no-featured-image-padding"],"yoast_head":"\n