[amp_mcq option1=”[Ph3P(Me) I]; PH3P=CH-CH2-CH2-CH3″ option2=”[Ph3P(Me)] [I]; Ph3P=CH2″ option3=”[Ph3P(Me)2]; Ph3P=CH2″ option4=”[Ph3P(Me)] [I]; Ph3″ correct=”option1″]<\/p>\n
The correct answer is $\\boxed{\\text{(A)}}$.<\/p>\n
In the reaction, $\\ce{Ph3P ->[Mel] [X] ->[n-BuLi] [Y]}$, the compound $\\ce{X}$ is a triphenylphosphonium iodide, $\\ce{[Ph3P(Me)I]}$. This is formed when the triphenylphosphine, $\\ce{Ph3P}$, reacts with methyl iodide, $\\ce{MeI}$, in the presence of a Lewis acid, such as $\\ce{Mel}$. The reaction is a nucleophilic substitution reaction, in which the iodide ion, $\\ce{I-}$, attacks the phosphorus atom in the triphenylphosphine, displacing the methyl group, $\\ce{Me}$.<\/p>\n
The compound $\\ce{Y}$ is a triphenylphosphine methylene, $\\ce{[Ph3P(Me)] [I]}$. This is formed when the triphenylphosphonium iodide, $\\ce{[Ph3P(Me)I]}$, reacts with n-butyllithium, $\\ce{n-BuLi}$. The reaction is a lithium-halogen exchange reaction, in which the lithium ion, $\\ce{Li+}$, attacks the iodide ion, $\\ce{I-}$, displacing the methyl group, $\\ce{Me}$.<\/p>\n
The other options are incorrect. Option $\\text{(B)}$ is incorrect because it does not have a methylene group, $\\ce{CH2}$. Option $\\text{(C)}$ is incorrect because it does not have an iodide ion, $\\ce{I-}$. Option $\\text{(D)}$ is incorrect because it does not have a triphenylphosphonium ion, $\\ce{[Ph3P(Me)I]}$.<\/p>\n","protected":false},"excerpt":{"rendered":"
[amp_mcq option1=”[Ph3P(Me) I]; PH3P=CH-CH2-CH2-CH3″ option2=”[Ph3P(Me)] [I]; Ph3P=CH2″ option3=”[Ph3P(Me)2]; Ph3P=CH2″ option4=”[Ph3P(Me)] [I]; Ph3″ correct=”option1″]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[688],"tags":[],"class_list":["post-19913","post","type-post","status-publish","format-standard","hentry","category-basics-of-organic-reaction-mechanism","no-featured-image-padding"],"yoast_head":"\n