[amp_mcq option1=”3-hexyne” option2=”2-hexyne” option3=”2, 3-hexadiene” option4=”2, 4-hexadiene” correct=”option1″]<\/p>\n
The correct answer is $\\boxed{\\text{C}}$, 2,3-hexadiene.<\/p>\n
(E)-3-bromo-3-hexene is a conjugated alkene. When treated with a strong base, such as $\\ce{CH3O-}$ in $\\ce{CH3OH}$, it undergoes an E2 elimination reaction to form a conjugated diene. The elimination reaction proceeds via a concerted mechanism, with the proton and the leaving group departing in the same step. The product of the elimination reaction is 2,3-hexadiene, which is a conjugated diene. Conjugated dienes are more stable than isolated double bonds, and therefore the elimination reaction is favored.<\/p>\n
The other options are incorrect because they do not represent the product of an E2 elimination reaction. Option A, 3-hexyne, is an alkyne. Alkynes are less stable than alkenes, and therefore the elimination reaction would not produce an alkyne. Option B, 2-hexyne, is also an alkyne. Option C, 2,3-hexadiene, is a conjugated diene, but it is not the product of an E2 elimination reaction. Option D, 2,4-hexadiene, is a conjugated diene, but it is not the product of an E2 elimination reaction.<\/p>\n","protected":false},"excerpt":{"rendered":"
[amp_mcq option1=”3-hexyne” option2=”2-hexyne” option3=”2, 3-hexadiene” option4=”2, 4-hexadiene” correct=”option1″]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[688],"tags":[],"class_list":["post-19899","post","type-post","status-publish","format-standard","hentry","category-basics-of-organic-reaction-mechanism","no-featured-image-padding"],"yoast_head":"\n