B. Vin = 0<\/strong>.<\/p>\nIn a depletion-mode MOSFET, the channel is initially depleted of charge carriers, so there is no current flow when a voltage is applied to the gate. However, when a voltage is applied to the gate that is greater than the threshold voltage, the channel becomes conductive and current flows. This current flow is what causes the dissipation in a depletion-mode pull-up.<\/p>\n
In a depletion-mode pull-up, the MOSFET is connected in parallel with a resistor. When the input voltage (Vin) is high, the MOSFET is turned off and the resistor provides the only path for current to flow. This results in a small amount of dissipation. However, when the input voltage is low, the MOSFET is turned on and current flows through the MOSFET and the resistor. This results in a much larger amount of dissipation.<\/p>\n
Therefore, the correct answer is: B. Vin = 0<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"[amp_mcq option1=”Vin = 1″ option2=”Vin = 0″ option3=”Vout = 1″ option4=”Vout = 0″ correct=”option2″]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[687],"tags":[],"class_list":["post-19783","post","type-post","status-publish","format-standard","hentry","category-vlsi-design-and-testing","no-featured-image-padding"],"yoast_head":"\n
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