[amp_mcq option1=”More” option2=”Less” option3=”All of the mentioned” option4=”None of the mentioned” correct=”option2″]<\/p>\n
The correct answer is: B. Less<\/strong><\/p>\n Leakage current is the current that flows through a MOSFET when it is turned off. It is caused by the movement of minority carriers through the channel. The threshold voltage is the voltage at which the MOSFET turns on. When the threshold voltage is higher, the channel is narrower and there is less space for minority carriers to flow. This means that the leakage current will be less.<\/p>\n Option A is incorrect because leakage current is inversely proportional to the threshold voltage. When the threshold voltage is higher, the leakage current will be less.<\/p>\n Option C is incorrect because leakage current is not always more when the threshold voltage is more. In fact, as explained above, leakage current is inversely proportional to the threshold voltage.<\/p>\n Option D is incorrect because leakage current is a real phenomenon that can be observed in MOSFETs.<\/p>\n","protected":false},"excerpt":{"rendered":" [amp_mcq option1=”More” option2=”Less” option3=”All of the mentioned” option4=”None of the mentioned” correct=”option2″]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[687],"tags":[],"class_list":["post-19779","post","type-post","status-publish","format-standard","hentry","category-vlsi-design-and-testing","no-featured-image-padding"],"yoast_head":"\n