{"id":19175,"date":"2024-04-15T05:35:59","date_gmt":"2024-04-15T05:35:59","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=19175"},"modified":"2024-04-15T05:35:59","modified_gmt":"2024-04-15T05:35:59","slug":"nortons-theorem-replaces-a-complicated-circuit-facing-a-load-by-an-a-ideal-voltage-source-and-parallel-resistor-b-ideal-current-source-and-parallel-resistor-c-ideal-voltage-source-and-series-resi","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/nortons-theorem-replaces-a-complicated-circuit-facing-a-load-by-an-a-ideal-voltage-source-and-parallel-resistor-b-ideal-current-source-and-parallel-resistor-c-ideal-voltage-source-and-series-resi\/","title":{"rendered":"Norton’s theorem replaces a complicated circuit facing a load by an A. Ideal voltage source and parallel resistor B. Ideal current source and parallel resistor C. Ideal voltage source and series resistor D. Ideal current source and series resistor E. None of the above"},"content":{"rendered":"

[amp_mcq option1=”Ideal voltage source and parallel resistor” option2=”Ideal current source and parallel resistor” option3=”Ideal voltage source and series resistor” option4=”Ideal current source and series resistor E. None of the above” correct=”option3″]<\/p>\n

Norton’s theorem states that a linear bilateral network can be replaced with an equivalent current source in parallel with a resistor. The equivalent current source is equal to the short-circuit current at the terminals of the network, and the equivalent resistor is equal to the open-circuit voltage divided by the short-circuit current.<\/p>\n

Option A is correct. Norton’s theorem replaces a complicated circuit facing a load by an ideal current source and parallel resistor. The ideal current source is equal to the short-circuit current at the terminals of the network, and the parallel resistor is equal to the open-circuit voltage divided by the short-circuit current.<\/p>\n

Option B is incorrect. Norton’s theorem does not replace a complicated circuit facing a load by an ideal voltage source and parallel resistor.<\/p>\n

Option C is incorrect. Norton’s theorem does not replace a complicated circuit facing a load by an ideal voltage source and series resistor.<\/p>\n

Option D is incorrect. Norton’s theorem does not replace a complicated circuit facing a load by an ideal current source and series resistor.<\/p>\n

Option E is incorrect. Norton’s theorem is a valid theorem that can be used to simplify the analysis of complicated circuits.<\/p>\n","protected":false},"excerpt":{"rendered":"

[amp_mcq option1=”Ideal voltage source and parallel resistor” option2=”Ideal current source and parallel resistor” option3=”Ideal voltage source and series resistor” option4=”Ideal current source and series resistor E. None of the above” correct=”option3″]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[682],"tags":[],"class_list":["post-19175","post","type-post","status-publish","format-standard","hentry","category-electronic-principles","no-featured-image-padding"],"yoast_head":"\nNorton's theorem replaces a complicated circuit facing a load by an A. Ideal voltage source and parallel resistor B. Ideal current source and parallel resistor C. Ideal voltage source and series resistor D. Ideal current source and series resistor E. 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