{"id":19169,"date":"2024-04-15T05:35:54","date_gmt":"2024-04-15T05:35:54","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=19169"},"modified":"2024-04-15T05:35:54","modified_gmt":"2024-04-15T05:35:54","slug":"which-one-of-the-following-equations-most-directly-leads-to-the-resistance-of-an-ordinary-household-light-bulb-assuming-that-you-know-the-power-and-voltage-rating-a-r-e2-p-b-p-pr-c-p-e2-r-d","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-equations-most-directly-leads-to-the-resistance-of-an-ordinary-household-light-bulb-assuming-that-you-know-the-power-and-voltage-rating-a-r-e2-p-b-p-pr-c-p-e2-r-d\/","title":{"rendered":"Which one of the following equations most directly leads to the resistance of an ordinary household light bulb, assuming that you know the power and voltage rating? A. R = E2\/P B. P = PR C. P = E2\/R D. I = P\/E E. None of the above"},"content":{"rendered":"<p>[amp_mcq option1=&#8221;R = E2\/P&#8221; option2=&#8221;P = PR&#8221; option3=&#8221;P = E2\/R&#8221; option4=&#8221;I = P\/E E. None of the above&#8221; correct=&#8221;option1&#8243;]<!--more--><\/p>\n<p>The correct answer is: A. R = E2\/P<\/p>\n<p>The power (P) of an ordinary household light bulb is the product of the voltage (E) and the current (I). The resistance (R) of the light bulb is the ratio of the voltage to the current. Therefore, the resistance of the light bulb can be calculated using the following equation:<\/p>\n<p>R = E2\/P<\/p>\n<p>Option B is incorrect because it states that the power is equal to the product of the resistance and the current. This is not correct, as the power is equal to the product of the voltage and the current.<\/p>\n<p>Option C is incorrect because it states that the power is equal to the square of the voltage divided by the resistance. This is not correct, as the power is equal to the product of the voltage and the current.<\/p>\n<p>Option D is incorrect because it states that the current is equal to the power divided by the voltage. This is not correct, as the current is equal to the voltage divided by the resistance.<\/p>\n<p>Option E is incorrect because it states that none of the above equations leads to the resistance of an ordinary household light bulb. However, option A is the only equation that leads to the resistance of an ordinary household light bulb.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>[amp_mcq option1=&#8221;R = E2\/P&#8221; option2=&#8221;P = PR&#8221; option3=&#8221;P = E2\/R&#8221; option4=&#8221;I = P\/E E. None of the above&#8221; correct=&#8221;option1&#8243;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[682],"tags":[],"class_list":["post-19169","post","type-post","status-publish","format-standard","hentry","category-electronic-principles","no-featured-image-padding"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Which one of the following equations most directly leads to the resistance of an ordinary household light bulb, assuming that you know the power and voltage rating? A. R = E2\/P B. P = PR C. P = E2\/R D. I = P\/E E. None of the above<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-equations-most-directly-leads-to-the-resistance-of-an-ordinary-household-light-bulb-assuming-that-you-know-the-power-and-voltage-rating-a-r-e2-p-b-p-pr-c-p-e2-r-d\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Which one of the following equations most directly leads to the resistance of an ordinary household light bulb, assuming that you know the power and voltage rating? A. R = E2\/P B. P = PR C. P = E2\/R D. I = P\/E E. None of the above\" \/>\n<meta property=\"og:description\" content=\"[amp_mcq option1=&#8221;R = E2\/P&#8221; option2=&#8221;P = PR&#8221; option3=&#8221;P = E2\/R&#8221; option4=&#8221;I = P\/E E. 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A. R = E2\/P B. P = PR C. P = E2\/R D. I = P\/E E. None of the above","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/which-one-of-the-following-equations-most-directly-leads-to-the-resistance-of-an-ordinary-household-light-bulb-assuming-that-you-know-the-power-and-voltage-rating-a-r-e2-p-b-p-pr-c-p-e2-r-d\/","og_locale":"en_US","og_type":"article","og_title":"Which one of the following equations most directly leads to the resistance of an ordinary household light bulb, assuming that you know the power and voltage rating? A. R = E2\/P B. P = PR C. P = E2\/R D. I = P\/E E. None of the above","og_description":"[amp_mcq option1=&#8221;R = E2\/P&#8221; option2=&#8221;P = PR&#8221; option3=&#8221;P = E2\/R&#8221; option4=&#8221;I = P\/E E. 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