{"id":19094,"date":"2024-04-15T05:34:54","date_gmt":"2024-04-15T05:34:54","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=19094"},"modified":"2024-04-15T05:34:54","modified_gmt":"2024-04-15T05:34:54","slug":"doubling-the-operating-frequency-of-an-inductive-circuit-a-has-no-effect-on-the-inductive-reactance-b-doubles-the-amount-of-inductive-reactance-c-multiplies-the-inductive-reactance-by-6-28-d-cuts","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/doubling-the-operating-frequency-of-an-inductive-circuit-a-has-no-effect-on-the-inductive-reactance-b-doubles-the-amount-of-inductive-reactance-c-multiplies-the-inductive-reactance-by-6-28-d-cuts\/","title":{"rendered":"Doubling the operating frequency of an inductive circuit: A. has no effect on the inductive reactance B. doubles the amount of inductive reactance C. multiplies the inductive reactance by 6.28 D. cuts the inductive reactance in half E. None of the above"},"content":{"rendered":"<p>\r\n    <!-- Check if it's an AMP page -->\r\n            <!-- Non-AMP version -->\r\n        <div class=\"mcq-container\" data-quiz-id=\"quizState_6abed7c9e8c9f\">\r\n                                            <div class=\"option\" data-option-key=\"option1\" data-is-correct=\"false\">\r\n                    has no effect on the inductive reactance                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option2\" data-is-correct=\"true\">\r\n                    doubles the amount of inductive reactance                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option3\" data-is-correct=\"false\">\r\n                    multiplies the inductive reactance by 6.28                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option4\" data-is-correct=\"false\">\r\n                    cuts the inductive reactance in half E. None of the above                <\/div>\r\n                            \r\n            <!-- Feedback messages for non-AMP -->\r\n            <div class=\"feedback\" data-feedback=\"wrong\">Answer is Right!<\/div>\r\n            <div class=\"feedback\" data-feedback=\"right\">Answer is Wrong!<\/div>\r\n        <\/div>\r\n\r\n        <script>\r\n        document.addEventListener('DOMContentLoaded', function () {\r\n            var containers = document.querySelectorAll('.mcq-container');\r\n\r\n            containers.forEach(function(container) {\r\n                var options = container.querySelectorAll('.option');\r\n                var feedbackSelect = container.querySelector('[data-feedback=\"select\"]');\r\n                var feedbackWrong = container.querySelector('[data-feedback=\"wrong\"]');\r\n                var feedbackRight = container.querySelector('[data-feedback=\"right\"]');\r\n\r\n                options.forEach(function(option) {\r\n                    option.addEventListener('click', function() {\r\n                        var selectedOption = option.getAttribute('data-option-key');\r\n                        var isCorrect = option.getAttribute('data-is-correct') === 'true';\r\n\r\n                        \/\/ Remove previous selections\r\n                        options.forEach(function(opt) {\r\n                            opt.classList.remove('correct', 'incorrect');\r\n                        });\r\n\r\n                        \/\/ Add the correct\/incorrect class\r\n                        if (isCorrect) {\r\n                            option.classList.add('correct');\r\n                            feedbackRight.hidden = false;\r\n                            feedbackWrong.hidden = true;\r\n                        } else {\r\n                            option.classList.add('incorrect');\r\n                            feedbackRight.hidden = true;\r\n                            feedbackWrong.hidden = false;\r\n                        }\r\n\r\n                        \/\/ Hide select feedback\r\n                        feedbackSelect.hidden = true;\r\n                    });\r\n                });\r\n            });\r\n        });\r\n        <\/script>\r\n    \r\n    <!--more--><\/p>\n<p>The correct answer is: <strong>B. doubles the amount of inductive reactance<\/strong>.<\/p>\n<p>Inductive reactance is the opposition to the flow of alternating current (AC) in a circuit that contains an inductor. It is measured in ohms (\u00ce\u00a9) and is given by the formula:<\/p>\n<p>$X_L = 2\\pi f L$<\/p>\n<p>where:<\/p>\n<ul>\n<li>$X_L$ is the inductive reactance in ohms (\u00ce\u00a9)<\/li>\n<li>$f$ is the frequency <div class=\"youtube-subscribe-container\">\r\n        <a href=\"https:\/\/www.youtube.com\/channel\/UCNHT8lW-JmLC68rjBfZhdkg?sub_confirmation=1\" target=\"_blank\" class=\"youtube-subscribe-button\">\r\n            <span class=\"youtube-icon\">\r\n                <svg xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 576 512\">\r\n                    <path d=\"M549.7 124.1c-6.3-23.7-24.8-42.3-48.3-48.6C458.8 64 288 64 288 64S117.2 64 74.6 75.5c-23.5 6.3-42 24.9-48.3 48.6-11.4 42.9-11.4 132.3-11.4 132.3s0 89.4 11.4 132.3c6.3 23.7 24.8 41.5 48.3 47.8C117.2 448 288 448 288 448s170.8 0 213.4-11.5c23.5-6.3 42-24.2 48.3-47.8 11.4-42.9 11.4-132.3 11.4-132.3s0-89.4-11.4-132.3zm-317.5 213.5V175.2l142.7 81.2-142.7 81.2z\"\/>\r\n                <\/svg>\r\n            <\/span>\r\n            Subscribe on YouTube\r\n        <\/a>\r\n    <\/div> of the AC current in hertz (Hz)<\/li>\n<li>$L$ is the inductance of the inductor in henries (H)<\/li>\n<\/ul>\n<p>As you can see from the formula, inductive reactance is directly proportional to the frequency of the AC current. This means that doubling the frequency of the AC current will double the inductive reactance.<\/p>\n<p>Option A is incorrect because doubling the frequency of the AC current will double the inductive reactance, not have no effect on it.<\/p>\n<p>Option C is incorrect because doubling the frequency of the AC current will double the inductive reactance, not multiply it by 6.28.<\/p>\n<p>Option D is incorrect because doubling the frequency of the AC current will double the <div class=\"telegram-channel-container\">\r\n        <a href=\"https:\/\/t.me\/pscnotes2025\" target=\"_blank\" class=\"telegram-channel-button\">\r\n            <span class=\"telegram-icon\">\r\n                <svg xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 496 512\">\r\n                    <path fill=\"white\" d=\"M248,8C111,8,0,119,0,256s111,248,248,248s248-111,248-248S385,8,248,8z M362,177L320,367c-3,14-10,18-20,14l-56-41l-27,26 c-3,3-5,5-10,5l4-63L323,196c5-5-1-7-8-3l-98,62l-42-13c-9-3-10-9,2-14l162-63C351,160,365,164,362,177z\"\/>\r\n                <\/svg>\r\n            <\/span>\r\n            Join Our Telegram Channel\r\n        <\/a>\r\n    <\/div> inductive reactance, not cut it in half.<\/p>\n<p>Option E is incorrect because doubling the frequency of the AC current will double the inductive reactance.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Join Our Telegram Channel Subscribe on YouTube<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[682],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Doubling the operating frequency of an inductive circuit: A. has no effect on the inductive reactance B. doubles the amount of inductive reactance C. multiplies the inductive reactance by 6.28 D. cuts the inductive reactance in half E. 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