[amp_mcq option1=”increasing the area of the plates” option2=”decreasing the area of the plates” option3=”increasing the frequency of the applied voltage” option4=”increasing the voltage applied to the plates E. None of the above” correct=”option1″]<\/p>\n
The correct answer is A. Increasing the area of the plates.<\/p>\n
The capacitance of a capacitor is given by the formula:<\/p>\n
$C = \\frac{\\epsilon_0 A}{d}$<\/p>\n
where $C$ is the capacitance, $\\epsilon_0$ is the permittivity of free space, $A$ is the area of the plates, and $d$ is the distance between the plates.<\/p>\n
Therefore, the capacitance is proportional to the area of the plates. Increasing the area of the plates will increase the capacitance.<\/p>\n
Option B is incorrect because decreasing the area of the plates will decrease the capacitance.<\/p>\n
Option C is incorrect because increasing the frequency of the applied voltage will not affect the capacitance.<\/p>\n
Option D is incorrect because increasing the voltage applied to the plates will not affect the capacitance.<\/p>\n
Option E is incorrect because increasing the area of the plates is the only way to increase the capacitance.<\/p>\n","protected":false},"excerpt":{"rendered":"
[amp_mcq option1=”increasing the area of the plates” option2=”decreasing the area of the plates” option3=”increasing the frequency of the applied voltage” option4=”increasing the voltage applied to the plates E. None of the above” correct=”option1″]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[682],"tags":[],"class_list":["post-19050","post","type-post","status-publish","format-standard","hentry","category-electronic-principles","no-featured-image-padding"],"yoast_head":"\n