{"id":18997,"date":"2024-04-15T05:33:32","date_gmt":"2024-04-15T05:33:32","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=18997"},"modified":"2024-04-15T05:33:32","modified_gmt":"2024-04-15T05:33:32","slug":"addition-of-1101012-and-1011112-is-a-11001002-b-11010002-c-11101112-d-1100112-e-none-of-the-above","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/addition-of-1101012-and-1011112-is-a-11001002-b-11010002-c-11101112-d-1100112-e-none-of-the-above\/","title":{"rendered":"Addition of 1101012 and 1011112 is A. 11001002 B. 11010002 C. 11101112 D. 1100112 E. None of the above"},"content":{"rendered":"<p>\r\n    <!-- Check if it's an AMP page -->\r\n            <!-- Non-AMP version -->\r\n        <div class=\"mcq-container\" data-quiz-id=\"quizState_6aba52767f1d6\">\r\n                                            <div class=\"option\" data-option-key=\"option1\" data-is-correct=\"false\">\r\n                    11001002                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option2\" data-is-correct=\"false\">\r\n                    11010002                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option3\" data-is-correct=\"true\">\r\n                    11101112                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option4\" data-is-correct=\"false\">\r\n                    1100112 E. None of the above                <\/div>\r\n                            \r\n            <!-- Feedback messages for non-AMP -->\r\n            <div class=\"feedback\" data-feedback=\"wrong\">Answer is Right!<\/div>\r\n            <div class=\"feedback\" data-feedback=\"right\">Answer is Wrong!<\/div>\r\n        <\/div>\r\n\r\n        <script>\r\n        document.addEventListener('DOMContentLoaded', function () {\r\n            var containers = document.querySelectorAll('.mcq-container');\r\n\r\n            containers.forEach(function(container) {\r\n                var options = container.querySelectorAll('.option');\r\n                var feedbackSelect = container.querySelector('[data-feedback=\"select\"]');\r\n                var feedbackWrong = container.querySelector('[data-feedback=\"wrong\"]');\r\n                var feedbackRight = container.querySelector('[data-feedback=\"right\"]');\r\n\r\n                options.forEach(function(option) {\r\n                    option.addEventListener('click', function() {\r\n                        var selectedOption = option.getAttribute('data-option-key');\r\n                        var isCorrect = option.getAttribute('data-is-correct') === 'true';\r\n\r\n                        \/\/ Remove previous selections\r\n                        options.forEach(function(opt) {\r\n                            opt.classList.remove('correct', 'incorrect');\r\n                        });\r\n\r\n                        \/\/ Add the correct\/incorrect class\r\n                        if (isCorrect) {\r\n                            option.classList.add('correct');\r\n                            feedbackRight.hidden = false;\r\n                            feedbackWrong.hidden = true;\r\n                        } else {\r\n                            option.classList.add('incorrect');\r\n                            feedbackRight.hidden = true;\r\n                            feedbackWrong.hidden = false;\r\n                        }\r\n\r\n                        \/\/ Hide select feedback\r\n                        feedbackSelect.hidden = true;\r\n                    });\r\n                });\r\n            });\r\n        });\r\n        <\/script>\r\n    \r\n    <!--more--><\/p>\n<p>The correct answer is $\\boxed{\\text{C. }11101112}$.<\/p>\n<p>To add two binary numbers, you line them up so that the corresponding digits are in the same column. Then, you add the digits in each column, carrying over any extra digits to the next column.<\/p>\n<p>In this case, we have:<\/p>\n<p>$$\\begin{array}{cc}<br \/>\n1 &amp; 1 &amp; 0 &amp; 1 &amp; 0 &amp; 1 \\<br \/>\n+ &amp; 1 &amp; 0 &amp; 1 &amp; 1 &amp; 1 \\<br \/>\n\\hline<br \/>\n1 &amp; 1 &amp; <div class=\"youtube-subscribe-container\">\r\n        <a href=\"https:\/\/www.youtube.com\/channel\/UCNHT8lW-JmLC68rjBfZhdkg?sub_confirmation=1\" target=\"_blank\" class=\"youtube-subscribe-button\">\r\n            <span class=\"youtube-icon\">\r\n                <svg xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 576 512\">\r\n                    <path d=\"M549.7 124.1c-6.3-23.7-24.8-42.3-48.3-48.6C458.8 64 288 64 288 64S117.2 64 74.6 75.5c-23.5 6.3-42 24.9-48.3 48.6-11.4 42.9-11.4 132.3-11.4 132.3s0 89.4 11.4 132.3c6.3 23.7 24.8 41.5 48.3 47.8C117.2 448 288 448 288 448s170.8 0 213.4-11.5c23.5-6.3 42-24.2 48.3-47.8 11.4-42.9 11.4-132.3 11.4-132.3s0-89.4-11.4-132.3zm-317.5 213.5V175.2l142.7 81.2-142.7 81.2z\"\/>\r\n                <\/svg>\r\n            <\/span>\r\n            Subscribe on YouTube\r\n        <\/a>\r\n    <\/div> 1 &amp; 0 &amp; 1 &amp; 0 \\<br \/>\n\\end{array}$$<\/p>\n<p>The answer is $\\boxed{\\text{C. }11101112}$.<\/p>\n<p>Here is a brief explanation of each option:<\/p>\n<ul>\n<li>Option A: $11001002$ is incorrect because the sum of the digits in the first column is $1+1+1+1=4$, which is greater than $2$. In binary, when you add two digits that are greater than $2$, you carry over the extra digit to the next column.<\/li>\n<li>Option B: $11010002$ is incorrect because the sum of the digits in the second column is $0+1+1+1=3$, which is greater than $2$. In binary, when you add two digits that are greater than $2$, you carry over the extra digit to the next column.<\/li>\n<li>Option C: $11101112$ is correct because the sum of the digits in each column is equal to the corresponding digit in the answer.<\/li>\n<li>Option D: $1100112$ is incorrect because the sum of the <div class=\"telegram-channel-container\">\r\n        <a href=\"https:\/\/t.me\/pscnotes2025\" target=\"_blank\" class=\"telegram-channel-button\">\r\n            <span class=\"telegram-icon\">\r\n                <svg xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 496 512\">\r\n                    <path fill=\"white\" d=\"M248,8C111,8,0,119,0,256s111,248,248,248s248-111,248-248S385,8,248,8z M362,177L320,367c-3,14-10,18-20,14l-56-41l-27,26 c-3,3-5,5-10,5l4-63L323,196c5-5-1-7-8-3l-98,62l-42-13c-9-3-10-9,2-14l162-63C351,160,365,164,362,177z\"\/>\r\n                <\/svg>\r\n            <\/span>\r\n            Join Our Telegram Channel\r\n        <\/a>\r\n    <\/div> digits in the third column is $1+1+1+1=4$, which is greater than $2$. In binary, when you add two digits that are greater than $2$, you carry over the extra digit to the next column.<\/li>\n<li>Option E: None of the above is correct because none of the other options are the correct answer.<\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>Join Our Telegram Channel Subscribe on YouTube<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[681],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Addition of 1101012 and 1011112 is A. 11001002 B. 11010002 C. 11101112 D. 1100112 E. 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