{"id":1181,"date":"2024-03-05T15:12:52","date_gmt":"2024-03-05T15:12:52","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=1181"},"modified":"2024-03-05T15:12:52","modified_gmt":"2024-03-05T15:12:52","slug":"a-train-increases-its-normal-speed-by-12-5-and-reaches-its-destination-20-minutes-earlier-what-is-the-actual-time-taken-by-the-train-in-the-journey","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/a-train-increases-its-normal-speed-by-12-5-and-reaches-its-destination-20-minutes-earlier-what-is-the-actual-time-taken-by-the-train-in-the-journey\/","title":{"rendered":"A train increases its normal speed by 12.5% and reaches its destination 20 minutes earlier. What is the actual time taken by the train in the journey?"},"content":{"rendered":"<p>[amp_mcq option1=&#8221;220 minutes&#8221; option2=&#8221;180 minutes&#8221; option3=&#8221;145 minutes&#8221; option4=&#8221;160 minutes&#8221; correct=&#8221;option2&#8243;]<!--more--><\/p>\n<p>The correct answer is (b).<\/p>\n<p>Let $x$ be the original time taken by the train. If the train increases its speed by 12.5%, then the new time taken is $\\frac{112.5}{100}x = \\frac{27}{20}x$. Since the new time is 20 minutes earlier, we have $\\frac{27}{20}x = x &#8211; 20$. Solving for $x$, we get $x = \\boxed{180}$ minutes.<\/p>\n<p>Option (a) is incorrect because it is the time taken by the train if it does not increase its speed. Option (c) is incorrect because it is the time taken by the train if it increases its speed by 25%. Option (d) is incorrect because it is the time taken by the train if it increases its speed by 50%.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>[amp_mcq option1=&#8221;220 minutes&#8221; option2=&#8221;180 minutes&#8221; option3=&#8221;145 minutes&#8221; option4=&#8221;160 minutes&#8221; correct=&#8221;option2&#8243;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[423],"tags":[],"class_list":["post-1181","post","type-post","status-publish","format-standard","hentry","category-speed-and-time","no-featured-image-padding"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>A train increases its normal speed by 12.5% and reaches its destination 20 minutes earlier. What is the actual time taken by the train in the journey?<\/title>\n<meta name=\"description\" content=\"Let $x$ be the original time taken by the train. If the train increases its speed by 12.5%, then the new time taken is $frac{112.5}{100}x = frac{27}{20}x$. Since the new time is 20 minutes earlier, we have $frac{27}{20}x = x - 20$. Solving for $x$, we get $x = boxed{180}$ minutes.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/a-train-increases-its-normal-speed-by-12-5-and-reaches-its-destination-20-minutes-earlier-what-is-the-actual-time-taken-by-the-train-in-the-journey\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"A train increases its normal speed by 12.5% and reaches its destination 20 minutes earlier. What is the actual time taken by the train in the journey?\" \/>\n<meta property=\"og:description\" content=\"Let $x$ be the original time taken by the train. If the train increases its speed by 12.5%, then the new time taken is $frac{112.5}{100}x = frac{27}{20}x$. Since the new time is 20 minutes earlier, we have $frac{27}{20}x = x - 20$. Solving for $x$, we get $x = boxed{180}$ minutes.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/a-train-increases-its-normal-speed-by-12-5-and-reaches-its-destination-20-minutes-earlier-what-is-the-actual-time-taken-by-the-train-in-the-journey\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2024-03-05T15:12:52+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"A train increases its normal speed by 12.5% and reaches its destination 20 minutes earlier. What is the actual time taken by the train in the journey?","description":"Let $x$ be the original time taken by the train. If the train increases its speed by 12.5%, then the new time taken is $frac{112.5}{100}x = frac{27}{20}x$. Since the new time is 20 minutes earlier, we have $frac{27}{20}x = x - 20$. Solving for $x$, we get $x = boxed{180}$ minutes.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/a-train-increases-its-normal-speed-by-12-5-and-reaches-its-destination-20-minutes-earlier-what-is-the-actual-time-taken-by-the-train-in-the-journey\/","og_locale":"en_US","og_type":"article","og_title":"A train increases its normal speed by 12.5% and reaches its destination 20 minutes earlier. What is the actual time taken by the train in the journey?","og_description":"Let $x$ be the original time taken by the train. If the train increases its speed by 12.5%, then the new time taken is $frac{112.5}{100}x = frac{27}{20}x$. Since the new time is 20 minutes earlier, we have $frac{27}{20}x = x - 20$. Solving for $x$, we get $x = boxed{180}$ minutes.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/a-train-increases-its-normal-speed-by-12-5-and-reaches-its-destination-20-minutes-earlier-what-is-the-actual-time-taken-by-the-train-in-the-journey\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2024-03-05T15:12:52+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/a-train-increases-its-normal-speed-by-12-5-and-reaches-its-destination-20-minutes-earlier-what-is-the-actual-time-taken-by-the-train-in-the-journey\/","url":"https:\/\/exam.pscnotes.com\/mcq\/a-train-increases-its-normal-speed-by-12-5-and-reaches-its-destination-20-minutes-earlier-what-is-the-actual-time-taken-by-the-train-in-the-journey\/","name":"A train increases its normal speed by 12.5% and reaches its destination 20 minutes earlier. What is the actual time taken by the train in the journey?","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2024-03-05T15:12:52+00:00","dateModified":"2024-03-05T15:12:52+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"Let $x$ be the original time taken by the train. If the train increases its speed by 12.5%, then the new time taken is $\\frac{112.5}{100}x = \\frac{27}{20}x$. Since the new time is 20 minutes earlier, we have $\\frac{27}{20}x = x - 20$. 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