Which two figures out of the following four have the same area (with s

Which two figures out of the following four have the same area (with same units) ?
(Figure 1: Right triangle with sides 14, 22, 90 degree angle)
(Figure 2: Square with side 12)
(Figure 3: Isosceles triangle with sides 22, 22, 22)
(Figure 4: Circle with radius 7)

1 and 3
1 and 2
2 and 4
1 and 4
This question was previously asked in
UPSC CAPF – 2009
Calculate the area of each figure:
Figure 1: Right triangle with legs 14 and 22.
Area₁ = (1/2) * base * height = (1/2) * 14 * 22 = 7 * 22 = 154 sq units.

Figure 2: Square with side 12.
Area₂ = side² = 12² = 144 sq units.

Figure 3: Isosceles triangle with sides 22, 22, 22. This is an equilateral triangle with side length 22.
Area₃ = (√3 / 4) * side² = (√3 / 4) * 22² = (√3 / 4) * 484 = 121√3 sq units.
Using √3 ≈ 1.732, Area₃ ≈ 121 * 1.732 ≈ 209.5 sq units.

Figure 4: Circle with radius 7.
Area₄ = π * radius² = π * 7² = 49π sq units.
Using the approximation π ≈ 22/7 (often used in problems involving multiples of 7):
Area₄ ≈ 49 * (22/7) = 7 * 22 = 154 sq units.

Comparing the areas:
Area₁ = 154
Area₂ = 144
Area₃ ≈ 209.5
Area₄ ≈ 154 (using π ≈ 22/7) or ≈ 153.9 (using π ≈ 3.14)

Figures 1 and 4 have areas 154 and approximately 153.9 or exactly 154 if using π=22/7. The areas are essentially the same.

The key is to know the area formulas for the given geometric shapes and perform the calculations. In cases involving circles with radii that are multiples of 7, using the approximation π ≈ 22/7 often leads to exact integer or simple fraction results, which is a common hint in such problems to match areas with figures calculated using integers.
The side lengths 14 and 22 for the right triangle are chosen such that their product divided by 2 is 154. The radius 7 for the circle is chosen such that $\pi r^2$ is close to 154, and exactly 154 when using the common approximation $\pi \approx 22/7$. The square and equilateral triangle areas result in different values.