Which one of the following ions is not iso-electronic with F⁻ ?

Which one of the following ions is not iso-electronic with F⁻ ?

O²⁻
Na⁺
Ne
N⁻
This question was previously asked in
UPSC NDA-2 – 2021
The correct option is D. Iso-electronic species are atoms or ions that have the same number of electrons. We need to find which species among the options does not have the same number of electrons as F⁻.
A neutral Fluorine atom (F) has 9 electrons (atomic number = 9). The F⁻ ion has gained one electron, so it has $9 + 1 = 10$ electrons.
Let’s find the number of electrons for each option:
A) O²⁻: Neutral Oxygen (O) has 8 electrons (atomic number = 8). O²⁻ has gained two electrons, so $8 + 2 = 10$ electrons.
B) Na⁺: Neutral Sodium (Na) has 11 electrons (atomic number = 11). Na⁺ has lost one electron, so $11 – 1 = 10$ electrons.
C) Ne: Neutral Neon (Ne) has 10 electrons (atomic number = 10).
D) N⁻: Neutral Nitrogen (N) has 7 electrons (atomic number = 7). N⁻ has gained one electron, so $7 + 1 = 8$ electrons.
Thus, N⁻ has 8 electrons, while F⁻ has 10 electrons. N⁻ is not isoelectronic with F⁻.
Isoelectronic species often have similar chemical and physical properties due to having the same electron configuration. The species O²⁻, F⁻, Ne, Na⁺, Mg²⁺, Al³⁺ are all isoelectronic with 10 electrons, having the electron configuration of Neon.