Which of the following statements will assign the address of the age variable to the agePtr pointer?

”agePtr
”agePtr
”&agePtr
”*agePtr

The correct answer is A. agePtr = &age;

A pointer is a variable that stores the address of another variable. The statement agePtr = &age; assigns the address of the variable age to the pointer variable agePtr. This means that agePtr now points to the variable age.

The statement agePtr = *age; would dereference the pointer agePtr and assign the value of the variable pointed to by agePtr to agePtr. This would not assign the address of age to agePtr.

The statement &agePtr = age; would assign the address of the pointer agePtr to the variable age. This would not assign the address of age to agePtr.

The statement *agePtr = age; would dereference the pointer agePtr and assign the value of the variable pointed to by agePtr to the variable age. This would not assign the address of age to agePtr.

The statement agePtr -> *age; is not valid C++ syntax.