The correct answer is (d) Mau. Mau district has the highest sex ratio in Uttar Pradesh, with 963 females per 1000 males. This is significantly higher than the state average of 912 females per 1000 males.
Azamgarh, Jaunpur, and Deoria are all districts in Uttar Pradesh with relatively low sex ratios. Azamgarh has a sex ratio of 902 females per 1000 males, Jaunpur has a sex ratio of 904 females per 1000 males, and Deoria has a sex ratio of 906 females per 1000 males.
There are a number of factors that contribute to the low sex ratio in these districts. One factor is female infanticide, which is the practice of killing female infants at birth. Another factor is female feticide, which is the practice of aborting female fetuses. These practices are often carried out due to a preference for sons over daughters.
Another factor that contributes to the low sex ratio is the high rate of migration of men from these districts. Men often migrate to other parts of India or to other countries in search of work. This leaves a large number of women behind, which can lead to an imbalance in the sex ratio.
The low sex ratio in these districts has a number of negative consequences. One consequence is that it can lead to a shortage of women of marriageable age. This can make it difficult for men to find wives, and can also lead to an increase in the number of marriages between close relatives.
Another consequence of the low sex ratio is that it can lead to an increase in the number of single mothers. This can have a negative impact on the economic and social status of these women and their children.
The low sex ratio in these districts is a serious problem that needs to be addressed. There are a number of things that can be done to improve the situation, such as raising awareness of the issue, providing support to families with daughters, and cracking down on the practice of female infanticide and feticide.