When the sun is 30° above the horizon, shadow of one tree is 17·3 m lo

When the sun is 30° above the horizon, shadow of one tree is 17·3 m long. What is the height of this tree ?

20 m
17·30 m
10 m
1·73 m
This question was previously asked in
UPSC NDA-1 – 2015
This problem can be solved using trigonometry, specifically the tangent function in a right-angled triangle.
The tree stands vertically, forming a right angle with the ground. The sun’s rays create a shadow on the ground. The angle of elevation of the sun (30°) is the angle between the ground (shadow) and the line from the end of the shadow to the top of the tree. Let H be the height of the tree (opposite side) and L be the length of the shadow (adjacent side). We have the relationship: tan(angle) = Opposite / Adjacent. So, tan(30°) = H / L.
Given L = 17.3 m and tan(30°) = 1/$\sqrt{3}$.
H = L * tan(30°) = 17.3 m * (1/$\sqrt{3}$).
The value of $\sqrt{3}$ is approximately 1.732.
H $\approx$ 17.3 / 1.732.
Notice that 17.3 is very close to 10 * 1.73. If we assume the shadow length is precisely $10\sqrt{3}$ meters (which is approximately 17.32 m), then:
H = $(10\sqrt{3}) \times (1/\sqrt{3}) = 10$ meters.
Given the options, 10 m is the most likely intended answer, implying the shadow length 17.3 m was an approximation for $10\sqrt{3}$ m.
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