The correct answer is $\boxed{\text{C}}$, 445 ohms.
To find the total resistance of a parallel circuit, we use the following formula:
$$R_T = \frac{1}{R_1} + \frac{1}{R_2} + \cdots + \frac{1}{R_n}$$
In this case, we have two resistors, $R_1 = 220 \Omega$ and $R_2 = 470 \Omega$. Substituting these values into the formula, we get:
$$R_T = \frac{1}{220 \Omega} + \frac{1}{470 \Omega} = 445 \Omega$$
Option A is incorrect because it is the resistance of one of the resistors in the circuit. Option B is incorrect because it is the average of the resistances of the two resistors. Option C is correct because it is the total resistance of the parallel circuit. Option D is incorrect because it is the sum of the resistances of the two resistors. Option E is incorrect because it is not one of the possible answers.