What is the power dissipation of a resistance that has 24 V dropped across it and 0.25 A flowing through it? A. 3 W B. 6 W C. 64 W D. 122 W E. None of the above

[amp_mcq option1=”3 W” option2=”6 W” option3=”64 W” option4=”122 W E. None of the above” correct=”option3″]

The correct answer is $\boxed{\text{B) 6 W}}$.

The power dissipated by a resistor is given by the equation $P = I^2R$, where $I$ is the current flowing through the resistor and $R$ is the resistance of the resistor. In this case, we are given that $I = 0.25 A$ and $R = 24 \Omega$. Substituting these values into the equation, we get $P = (0.25 A)^2(24 \Omega) = 6 W$.

Option A is incorrect because it is the power dissipated by a resistor with 12 V dropped across it and 0.25 A flowing through it. Option C is incorrect because it is the power dissipated by a resistor with 24 V dropped across it and 1 A flowing through it. Option D is incorrect because it is the power dissipated by a resistor with 48 V dropped across it and 0.5 A flowing through it. Option E is incorrect because it is not one of the possible answers.

Exit mobile version