The correct answer is $\boxed{\text{B. 26.6 degree}}$.
In a parallel RLC circuit, the phase angle between the current and voltage is given by:
$$\phi = \arctan \left(\frac{X_L}{R}\right)$$
where $X_L$ is the inductive reactance and $R$ is the resistance.
In this case, we are given that $R = 100 \Omega$ and $X_L = 200 \Omega$. Substituting these values into the equation, we get:
$$\phi = \arctan \left(\frac{200 \Omega}{100 \Omega}\right) = 26.6^\circ$$
Therefore, the phase shift between the total current and voltage is 26.6 degrees.
Option A is incorrect because it is the phase angle between the current and voltage in a purely resistive circuit. In a purely resistive circuit, there is no inductive reactance, so the phase angle is 0 degrees.
Option C is incorrect because it is the phase angle between the current and voltage in a purely inductive circuit. In a purely inductive circuit, there is no resistive component, so the phase angle is 90 degrees.
Option D is incorrect because it is the phase angle between the current and voltage in a purely capacitive circuit. In a purely capacitive circuit, there is no inductive component, so the phase angle is 180 degrees.
Option E is incorrect because it is not a valid option.