Two generators A and B have 6 poles each. Generator A has wave wound armature while generator B has lap wound armature. The ratio of the induced e.m.f. is generator A and B will be

The correct answer is $\boxed{\text{C}}$.

The induced emf in a generator is proportional to the number of turns in the armature winding. Generator A has a wave wound armature, which means that there are two parallel paths through the armature winding. Generator B has a lap wound armature, which means that there are three parallel paths through the armature winding. Therefore, the induced emf in generator B is 1.5 times the induced emf in generator A.

Here is a more detailed explanation of each option:

• Option A: This option is incorrect because the induced emf in generator A is not twice the induced emf in generator B.
• Option B: This option is incorrect because the induced emf in generator B is not three times the induced emf in generator A.
• Option C: This option is correct because the induced emf in generator B is 1.5 times the induced emf in generator A.
• Option D: This option is incorrect because the induced emf in generator A is not three times the induced emf in generator B.