$$rac{3}{2}Omega $$
6 $$Omega $$
4 $$Omega $$
$$rac{8}{3}Omega $$
Answer is Wrong!
Answer is Right!
The correct answer is $\boxed{\frac{8}{3}\Omega}$.
To solve this, we can use the following formula for the equivalent resistance of three resistors connected in a triangle:
$$R_{eq} = \frac{1}{R_1 + R_2 + R_3}$$
In this case, we have $R_1 = R_2 = R_3 = 6\Omega$, so the equivalent resistance is:
$$R_{eq} = \frac{1}{6\Omega + 6\Omega + 6\Omega} = \frac{1}{18\Omega} = \boxed{\frac{8}{3}\Omega}$$
We can also solve this problem by considering the current that would flow through
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