There are four large urns numbered 1 to 4. The number of different ways all the three balls numbered 1 to 3 can be kept inside the four urns is
7
12
27
64
Answer is Right!
Answer is Wrong!
This question was previously asked in
UPSC CISF-AC-EXE – 2020
– We have 4 distinct urns (numbered 1, 2, 3, and 4).
– Each ball can be placed into any one of the four urns, and the placement of one ball does not affect the choices for the other balls.
– For Ball 1, there are 4 possible urns it can be placed in.
– For Ball 2, there are also 4 possible urns it can be placed in, independently of where Ball 1 was placed.
– For Ball 3, there are similarly 4 possible urns it can be placed in, independently of the placement of the other balls.
– The total number of ways to place all three balls is the product of the number of choices for each ball.
– Total ways = (Choices for Ball 1) * (Choices for Ball 2) * (Choices for Ball 3) = 4 * 4 * 4 = $4^3$.
– $4^3 = 64$.