The value of a capacitor can be made larger by: A. increasing the area of the plates B. decreasing the area of the plates C. increasing the frequency of the applied voltage D. increasing the voltage applied to the plates E. None of the above

[amp_mcq option1=”increasing the area of the plates” option2=”decreasing the area of the plates” option3=”increasing the frequency of the applied voltage” option4=”increasing the voltage applied to the plates E. None of the above” correct=”option1″]

The correct answer is A. Increasing the area of the plates.

The capacitance of a capacitor is given by the formula:

$C = \frac{\epsilon_0 A}{d}$

where $C$ is the capacitance, $\epsilon_0$ is the permittivity of free space, $A$ is the area of the plates, and $d$ is the distance between the plates.

Therefore, the capacitance is proportional to the area of the plates. Increasing the area of the plates will increase the capacitance.

Option B is incorrect because decreasing the area of the plates will decrease the capacitance.

Option C is incorrect because increasing the frequency of the applied voltage will not affect the capacitance.

Option D is incorrect because increasing the voltage applied to the plates will not affect the capacitance.

Option E is incorrect because increasing the area of the plates is the only way to increase the capacitance.