The correct answer is B. 500 W.
The total losses in a well designed D.C. generator of 10 kW will be nearly 500 W. These losses are due to various factors, such as copper losses, iron losses, and stray losses.
Copper losses are due to the resistance of the windings of the generator. These losses can be reduced by using thicker wire or by increasing the number of turns in the windings.
Iron losses are due to the magnetic hysteresis and eddy currents in the stator and rotor of the generator. These losses can be reduced by using high-quality steel for the stator and rotor and by using a laminated stator core.
Stray losses are due to leakage flux and radiation from the generator. These losses can be reduced by using a well-designed magnetic circuit and by using a proper insulation system.
The total losses in a well designed D.C. generator of 10 kW will be nearly 500 W. These losses can be reduced by using proper design techniques and by using high-quality materials.
Here is a brief explanation of each option:
- Option A: 100 W. This is too low. The total losses in a well designed D.C. generator of 10 kW will be much higher than 100 W.
- Option B: 500 W. This is the correct answer. The total losses in a well designed D.C. generator of 10 kW will be nearly 500 W.
- Option C: 1000 W. This is too high. The total losses in a well designed D.C. generator of 10 kW will be much lower than 1000 W.
- Option D: 1500 W. This is too high. The total losses in a well designed D.C. generator of 10 kW will be much lower than 1500 W.