The temperature of a body decreases from 240 K to 210 K. The correspon

The temperature of a body decreases from 240 K to 210 K. The corresponding change (without sign) in the temperature in degree Fahrenheit is close to :

[amp_mcq option1=”54° F” option2=”30° F” option3=”17° F” option4=”44° F” correct=”option1″]

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UPSC CISF-AC-EXE – 2023

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The temperature change from 240 K to 210 K is 30 K. The corresponding change in degree Fahrenheit is 54°F, which is option A.

A change in temperature on the Kelvin scale is equal to the same change in temperature on the Celsius scale (ΔT_K = ΔT_C). The relationship between a change in Celsius and a change in Fahrenheit is ΔT_F = (9/5) * ΔT_C.

Given the initial temperature T1 = 240 K and final temperature T2 = 210 K, the change in Kelvin is ΔT_K = T2 – T1 = 210 K – 240 K = -30 K. The question asks for the change *without sign*, so the magnitude of the change is 30 K. Since ΔT_K = ΔT_C, the change in Celsius is ΔT_C = 30°C. The corresponding change in Fahrenheit is ΔT_F = (9/5) * ΔT_C = (9/5) * 30 = 9 * 6 = 54°F.

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