The temperature of a body decreases from 240 K to 210 K. The correspon

The temperature of a body decreases from 240 K to 210 K. The corresponding change (without sign) in the temperature in degree Fahrenheit is close to :

54° F
30° F
17° F
44° F
This question was previously asked in
UPSC CISF-AC-EXE – 2023
The temperature change from 240 K to 210 K is 30 K. The corresponding change in degree Fahrenheit is 54°F, which is option A.
A change in temperature on the Kelvin scale is equal to the same change in temperature on the Celsius scale (ΔT_K = ΔT_C). The relationship between a change in Celsius and a change in Fahrenheit is ΔT_F = (9/5) * ΔT_C.
Given the initial temperature T1 = 240 K and final temperature T2 = 210 K, the change in Kelvin is ΔT_K = T2 – T1 = 210 K – 240 K = -30 K. The question asks for the change *without sign*, so the magnitude of the change is 30 K. Since ΔT_K = ΔT_C, the change in Celsius is ΔT_C = 30°C. The corresponding change in Fahrenheit is ΔT_F = (9/5) * ΔT_C = (9/5) * 30 = 9 * 6 = 54°F.