The correct answer is: C. Between 1 and 2.
A rolling cylinder has a speed that is greater than the speed of a sliding cylinder. This is because the rolling cylinder has to overcome both rolling resistance and friction, while the sliding cylinder only has to overcome friction. Rolling resistance is a force that opposes the rolling motion of a cylinder. It is caused by the deformation of the cylinder’s surface as it rolls over the ground. Friction is a force that opposes the relative motion of two surfaces that are in contact. It is caused by the adhesion of the two surfaces.
The ratio of the speed of a rolling cylinder to the speed of a sliding cylinder can be calculated using the following equation:
$v_r = \frac{v_s}{1 + \mu}$
where $v_r$ is the speed of the rolling cylinder, $v_s$ is the speed of the sliding cylinder, and $\mu$ is the coefficient of rolling friction. The coefficient of rolling friction is a dimensionless number that is less than 1. This means that the speed of a rolling cylinder is always greater than the speed of a sliding cylinder.
The ratio of the speed of a rolling cylinder to the speed of a sliding cylinder is between 1 and 2. This is because the coefficient of rolling friction is always less than 1.