The correct answer is: C. Sending end voltage is more.
The power transmitted in a transmission line is given by the following equation:
$$P = \frac{V_s^2}{R + jX}$$
where $V_s$ is the sending end voltage, $R$ is the resistance of the line, and $X$ is the reactance of the line.
The power transmitted is maximum when the sending end voltage is high. This is because the higher the sending end voltage, the higher the voltage drop across the resistance of the line. The lower the voltage drop across the resistance, the higher the power transmitted.
The reactance of the line has no effect on the power transmitted when the line is lossless. However, when the line has losses, the reactance of the line can affect the power transmitted. The higher the reactance, the lower the power transmitted.
Corona losses are a type of loss that occurs in transmission lines. Corona losses are caused by the ionization of the air around the conductors of the line. Corona losses can be reduced by increasing the diameter of the conductors or by using a higher voltage line.
The answer to the question is C. Sending end voltage is more.