The correct answer is: D. The output power available at the shaft
The power mentioned on the name plate of an electric motor indicates the output power available at the shaft. This is the power that is available to do work, such as turning a machine or lifting a load. The power drawn in kW is the power that the motor draws from the electrical supply. The power drawn in kVA is the apparent power, which is the product of the voltage and current. The gross power is the power that the motor would produce if it were 100% efficient. However, no motor is 100% efficient, so the output power available at the shaft is always less than the gross power.
Here is a brief explanation of each option:
- A. The power drawn in kW is the power that the motor draws from the electrical supply. This is the power that is used to turn the motor’s rotor. The power drawn in kW is equal to the product of the voltage and current.
- B. The power drawn in kVA is the apparent power, which is the product of the voltage and current. The apparent power is greater than the power drawn in kW because it includes the power that is lost in the motor’s windings.
- C. The gross power is the power that the motor would produce if it were 100% efficient. However, no motor is 100% efficient, so the output power available at the shaft is always less than the gross power.
- D. The output power available at the shaft is the power that is available to do work, such as turning a machine or lifting a load. This is the power that is indicated on the name plate of an electric motor.