The number of solutions of the simultaneous algebraic equation y = 3x + 3 and y = 3x + 5 is: A. zero B. 1 C. 2 D. Infinite

zero
1
2
Infinite

The correct answer is $\boxed{\text{C}}$.

To solve for $x$, we can subtract the two equations to get $0 = 3x$. Dividing both sides by 3, we get $x = 0$.

Substituting $x = 0$ into either of the original equations, we get $y = 3(0) + 3 = 3$. Therefore, the only solution is $(x, y) = (0, 3)$.

Option A is incorrect because there is at least one solution. Option B is incorrect because there are two solutions. Option D is incorrect because there are not infinitely many solutions.

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