The correct answer is $\boxed{\text{C}}$.
The maximum velocity of a body vibrating with a simple harmonic motion of amplitude $A$ and frequency $f$ is given by:
$$v_{max} = \omega A$$
where $\omega = 2\pi f$ is the angular frequency.
In this case, we have $A = 150 \text{ mm} = 0.15 \text{ m}$ and $f = 2 \text{ vibrations/sec} = 2 \pi \text{ rad/sec}$. Substituting these values into the equation for $v_{max}$, we get:
$$v_{max} = 2\pi (2 \pi) (0.15 \text{ m}) = 1.885 \text{ m/sec}$$
Option A is incorrect because it is too large. Option B is incorrect because it is too small. Option D is incorrect because it is much too small.