The major product formed in the following reaction is A. B. C. 50 : 50 mixture of above two compounds D.

nan
nan
50 : 50 mixture of above two compounds
nan

The major product formed in the following reaction is:

A. 2-butene
B. 1-butene
C. 1-butyne
D. 2-butyne

The correct answer is A. 2-butene.

The reaction is an elimination reaction, which means that a proton and an alkyl group are removed from the same carbon atom. The product of an elimination reaction is determined by the stability of the carbocation intermediate. In this case, the carbocation intermediate is a secondary carbocation, which is more stable than a primary carbocation. Therefore, the major product of the reaction is 2-butene, which is formed by the elimination of a proton and an isopropyl group from the same carbon atom.

Option B is incorrect because 1-butene is formed by the elimination of a proton and a methyl group from the same carbon atom. The carbocation intermediate in this case is a primary carbocation, which is less stable than a secondary carbocation. Therefore, 1-butene is not the major product of the reaction.

Option C is incorrect because 1-butyne is formed by the elimination of a proton and a hydrogen atom from the same carbon atom. The carbocation intermediate in this case is a primary carbocation, which is less stable than a secondary carbocation. Therefore, 1-butyne is not the major product of the reaction.

Option D is incorrect because a 50:50 mixture of 2-butene and 1-butene is not formed in this reaction. The major product of the reaction is 2-butene.