The magnitude of work done in moving an electron across two points having a potential difference 6 V is (electronic charge = 1.6 × 10⁻¹⁹ C)
1.2 × 10⁻¹⁹ J
9.6 × 10⁻¹⁹ J
4.8 × 10⁻¹⁹ J
1.6 × 10⁻¹⁹ J
Answer is Wrong!
Answer is Right!
This question was previously asked in
UPSC Geoscientist – 2023
Work done W = (1.6 × 10⁻¹⁹ C) × (6 V) = 9.6 × 10⁻¹⁹ Joules (J).
– Charge of an electron = 1.6 × 10⁻¹⁹ C.
– Units: Work done in Joules (J), charge in Coulombs (C), potential difference in Volts (V).