The magnitude of work done in moving an electron across two points hav

The magnitude of work done in moving an electron across two points having a potential difference 6 V is (electronic charge = 1.6 × 10⁻¹⁹ C)

[amp_mcq option1=”1.2 × 10⁻¹⁹ J” option2=”9.6 × 10⁻¹⁹ J” option3=”4.8 × 10⁻¹⁹ J” option4=”1.6 × 10⁻¹⁹ J” correct=”option2″]

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UPSC Geoscientist – 2023

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The work done (W) in moving a charge (q) across a potential difference (V) is given by the formula W = qV. In this case, the charge of the electron (q) is given as 1.6 × 10⁻¹⁹ C, and the potential difference (V) is 6 V.
Work done W = (1.6 × 10⁻¹⁹ C) × (6 V) = 9.6 × 10⁻¹⁹ Joules (J).

– Work done (W) = charge (q) × potential difference (V).
– Charge of an electron = 1.6 × 10⁻¹⁹ C.
– Units: Work done in Joules (J), charge in Coulombs (C), potential difference in Volts (V).

This work done represents the energy gained or lost by the charge as it moves through the potential difference. If an electron moves from a point of lower potential to a point of higher potential, positive work is done on it by the external field, and its potential energy increases. If it moves from higher to lower potential, the field does positive work, and its potential energy decreases. In this problem, the sign of work depends on the direction of movement relative to the potential difference, but the magnitude calculation remains W = |qV|.

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