The magnetic field strength of a current-carrying wire at a particular

The magnetic field strength of a current-carrying wire at a particular distance from the axis of the wire

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depends upon the current in the wire

depends upon the radius of the wire

depends upon the temperature of the surroundings

None of the above

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Answer is Wrong!

This question was previously asked in

UPSC NDA-2 – 2018

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The magnetic field strength of a current-carrying wire at a particular distance from the axis of the wire depends upon the current in the wire.

– The magnetic field strength (B) around a long straight current-carrying wire is given by the formula B = (μ₀ * I) / (2π * r).
– In this formula, I represents the current in the wire, and r represents the perpendicular distance from the axis of the wire.
– The magnetic field strength is directly proportional to the current (I).
– The magnetic field strength is inversely proportional to the distance (r).

μ₀ is the permeability of free space, a constant. The formula shows the direct dependence on current and distance, but not explicitly on the wire’s radius or surrounding temperature in the basic model for an external point. Temperature could indirectly affect the magnetic field by influencing the wire’s resistance and thus the current (if voltage is constant), but the fundamental relationship is B ∝ I for a given geometry.

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