The IR stretching frequencies (cm-1) for the compound X are as follows: 3300-3500 (s, br); 3000 (m); 2225 (s); 1680 (s). The correct assignment of the absorption bands is A. \[{\overline {\rm{V}} _{\left( {{\rm{OH}}} \right)}}\] = 3300-3500; \[{\overline {\rm{V}} _{\left( {{\rm{CH}}} \right)}}\] = 3000; \[{\overline {\rm{V}} _{\left( {{\rm{CN}}} \right)}}\] = 2225; \[{\overline {\rm{V}} _{\left( {{\rm{CO}}} \right)}}\] = 1680 B. \[{\overline {\rm{V}} _{\left( {{\rm{OH}}} \right)}}\] = 3000; \[{\overline {\rm{V}} _{\left( {{\rm{CH}}} \right)}}\] = 3300-3500; \[{\overline {\rm{V}} _{\left( {{\rm{CN}}} \right)}}\] = 2225; \[{\overline {\rm{V}} _{\left( {{\rm{CO}}} \right)}}\] = 1680 C. \[{\overline {\rm{V}} _{\left( {{\rm{OH}}} \right)}}\] = 3300-3500; \[{\overline {\rm{V}} _{\left( {{\rm{CH}}} \right)}}\] = 3000; \[{\overline {\rm{V}} _{\left( {{\rm{CN}}} \right)}}\] = 1680; \[{\overline {\rm{V}} _{\left( {{\rm{CO}}} \right)}}\] = 2225 D. \[{\overline {\rm{V}} _{\left( {{\rm{OH}}} \right)}}\] = 3000; \[{\overline {\rm{V}} _{\left( {{\rm{CH}}} \right)}}\] = 3300-3500; \[{\overline {\rm{V}} _{\left( {{\rm{CN}}} \right)}}\] = 1680; \[{\overline {\rm{V}} _{\left( {{\rm{CO}}} \right)}}\] = 2225

= 3300-3500; \[{\overline {\rm{V}} _{\left( {{\rm{CH}}} \right)}}\] = 3000; \[{\overline {\rm{V}} _{\left( {{\rm{CN}}} \right)}}\] = 2225; \[{\overline {\rm{V}} _{\left( {{\rm{CO}}} \right)}}\] = 1680″ option2=”\[{\overline {\rm{V}} _{\left( {{\rm{OH}}} \right)}}\] = 3000; \[{\overline {\rm{V}} _{\left( {{\rm{CH}}} \right)}}\] = 3300-3500; \[{\overline {\rm{V}} _{\left( {{\rm{CN}}} \right)}}\] = 2225; \[{\overline {\rm{V}} _{\left( {{\rm{CO}}} \right)}}\] = 1680″ option3=”\[{\overline {\rm{V}} _{\left( {{\rm{OH}}} \right)}}\] = 3300-3500; \[{\overline {\rm{V}} _{\left( {{\rm{CH}}} \right)}}\] = 3000; \[{\overline {\rm{V}} _{\left( {{\rm{CN}}} \right)}}\] = 1680; \[{\overline {\rm{V}} _{\left( {{\rm{CO}}} \right)}}\] = 2225″ option4=”\[{\overline {\rm{V}} _{\left( {{\rm{OH}}} \right)}}\] = 3000; \[{\overline {\rm{V}} _{\left( {{\rm{CH}}} \right)}}\] = 3300-3500; \[{\overline {\rm{V}} _{\left( {{\rm{CN}}} \right)}}\] = 1680; \[{\overline {\rm{V}} _{\left( {{\rm{CO}}} \right)}}\] = 2225″ correct=”option1″]

The correct answer is A.

The IR stretching frequencies (cm-1) for the compound X are as follows: 3300-3500 (s, br); 3000 (m); 2225 (s); 1680 (s).

The absorption band at 3300-3500 cm-1 is assigned to the O-H stretching vibration of an alcohol group. The absorption band at 3000 cm-1 is assigned to the C-H stretching vibration of an alkane group. The absorption band at 2225 cm-1 is assigned to the C≡N stretching vibration of a nitrile group. The absorption band at 1680 cm-1 is assigned to the C=O stretching vibration of a ketone group.

The absorption band at 3300-3500 cm-1 is broad and strong (s, br), which is characteristic of an alcohol group. The absorption band at 3000 cm-1 is medium and medium (m), which is characteristic of an alkane group. The absorption band at 2225 cm-1 is sharp and strong (s), which is characteristic of a nitrile group. The absorption band at 1680 cm-1 is sharp and strong (s), which is characteristic of a ketone group.

Therefore, the correct assignment of the absorption bands is A.

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Here are some additional details about the IR stretching frequencies of different functional groups:

• O-H stretching vibration of an alcohol group: 3300-3500 cm-1
• C-H stretching vibration of an alkane group: 3000 cm-1
• C≡N stretching vibration of a nitrile group: 2225 cm-1
• C=O stretching vibration of a ketone group: 1680 cm-1