The ionization energy of hydrogen atom in the ground state is
13.6 MeV
13.6 eV
13.6 Joule
Zero
Answer is Right!
Answer is Wrong!
This question was previously asked in
UPSC NDA-2 – 2017
The energy of an electron in the n-th energy level of a hydrogen atom is given by E_n = -13.6/n² eV. In the ground state (n=1), the energy is E₁ = -13.6/1² = -13.6 eV. At the ionization limit (n=infinity), the energy is E_infinity = -13.6/infinity² = 0 eV. The ionization energy is the difference between these energies: Ionization Energy = E_infinity – E₁ = 0 – (-13.6 eV) = +13.6 eV.