The following figure represents the velocity-time graph of a moving ca

The following figure represents the velocity-time graph of a moving car on a road:
Which segment of the graph represents the retardation?

AB
BC
CD
None
This question was previously asked in
UPSC NDA-2 – 2015
In a velocity-time (v-t) graph, acceleration is represented by the slope of the graph. Retardation (or deceleration) occurs when the acceleration is in the opposite direction to the velocity, causing the object to slow down. This corresponds to a negative slope in the v-t graph, assuming positive velocity.
– Segment AB has a positive slope, indicating positive acceleration (velocity increasing).
– Segment BC is horizontal, indicating zero slope and thus zero acceleration (constant velocity).
– Segment CD has a negative slope, indicating negative acceleration. Since the velocity is positive during this segment, a negative acceleration means retardation or deceleration (velocity decreasing).
The slope of a velocity-time graph represents acceleration. A negative slope indicates deceleration or retardation if the velocity is in the positive direction.
If the velocity were negative and the slope were positive, it would also represent slowing down (velocity increasing towards zero from a negative value). In this graph, velocity is positive throughout the plotted segments.