The figure shown above gives the time (t) versus position (x) graphs of three objects A, B and C. Which one of the following is the correct relation between their speeds $V_A$, $V_B$ and $V_C$, respectively at any instant (t > 0)?
[amp_mcq option1=”$V_A < V_B < V_C$" option2="$V_A > V_B > V_C$” option3=”$V_A = V_B = V_C \ne 0$” option4=”$V_A = V_B = V_C = 0$” correct=”option2″]
This question was previously asked in
UPSC NDA-1 – 2019
– A steeper slope indicates a higher speed, and a less steep slope indicates a lower speed.
– Examining the graph, the line for object A has the steepest slope.
– The line for object B has a slope less steep than A but steeper than C.
– The line for object C has the least steep slope.
– Since all slopes are positive, the objects are moving in the positive direction. The magnitude of the slope represents the speed.