The equation of 50 Hz current sine wave having r.m.s. value of 60 A is

60 sin 25 t
60 sin 50 t
84.84 sin 3141
42.42 sin 314 t

The correct answer is $\boxed{\text{B. }60 \sin 50 t}$.

The equation of a sine wave is $y = A \sin(2 \pi f t + \phi)$, where $A$ is the amplitude, $f$ is the frequency, $t$ is time, and $\phi$ is the phase angle.

In this case, the amplitude is $60 \text{ A}$, the frequency is $50 \text{ Hz}$, and the phase angle is $0$. Therefore, the equation of the sine wave is $y = 60 \sin(2 \pi 50 t)$, or $y = 60 \sin 50 t$.

Option A is incorrect because the frequency is $25 \text{ Hz}$, not $50 \text{ Hz}$.

Option C is incorrect because the amplitude is $84.84 \text{ A}$, not $60 \text{ A}$.

Option D is incorrect because the frequency is $314 \text{ Hz}$, not $50 \text{ Hz}$.

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