The eccentricity (e) of a hollow circular column, external diameter 25 cm, internal diameter 15 cm for an eccentric load 100 t for non-development of tension, is A. 2.75 cm B. 3.00 cm C. 3.50 cm D. 4.25 cm

[amp_mcq option1=”2.75 cm” option2=”3.00 cm” option3=”3.50 cm” option4=”4.25 cm” correct=”option1″]

The correct answer is A. 2.75 cm.

The eccentricity (e) of a hollow circular column is given by the following equation:

$$e = \frac{r_o^2 – r_i^2}{2}$$

where $r_o$ is the outer radius of the column and $r_i$ is the inner radius of the column.

In this case, $r_o = 25\text{ cm}$ and $r_i = 15\text{ cm}$. Substituting these values into the equation, we get:

$$e = \frac{(25\text{ cm})^2 – (15\text{ cm})^2}{2} = 2.75\text{ cm}$$

Therefore, the eccentricity of the hollow circular column is 2.75 cm.

The other options are incorrect because they do not represent the correct value of the eccentricity.