Home » mcq » Civil engineering » Waste water engineering » The drainage area of a town is 12 hectares. Its 40% area is hard pavement (K = 0.85), the 40% area is unpaved streets (K = 0.20) and the remaining is wooded areas (K = 0.15). Assuming the time of concentration for the areas as 30 minutes and using the formula $${{\text{P}}_{\text{s}}} = \frac{{900}}{{{\text{t}} + 60}}$$ the maximum run off is A. 0.10 cumec B. 0.12 cumec C. 0.15 cumec D. 0.20 cumec
0.10 cumec
0.12 cumec
0.15 cumec
0.20 cumec
Answer is Wrong!
Answer is Right!
The correct answer is $\boxed{\text{B}. 0.12 \text{ cumec}}$.
The peak discharge $Q_p$ is given by the formula:
$$Q_p = \frac{K A}{\tau}$$
where:
- $K$ is the runoff coefficient
- $A$ is the drainage area
- $\tau$ is the time of concentration
The runoff coefficient $K$ is a dimensionless number that represents the fraction of precipitation that will runoff. It depends on the land use and surface characteristics. For hard pavement, $K = 0.85$. For unpaved streets, $K = 0.20$. For wooded areas, $K = 0.15$.
The drainage area $A$ is given to be 12 hectares.
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The time of concentration $\tau$ is given to be 30 minutes.
Substituting these values into the formula, we get:
$$Q_p = \frac{0.85 \times 12 \text{ ha}}{{30 \text{ min}} \times \frac{60 \text{ min}}{1 \text{ hour}}} = 0.12 \text{ cumec}$$
Therefore, the maximum runoff is $\boxed{\text{B}. 0.12 \text{ cumec}}$.
The other options are incorrect because they do not represent the correct value of the peak discharge.