The cost of energy to operate an industrial refrigerator that consumes

The cost of energy to operate an industrial refrigerator that consumes 5 kW power working 10 hours per day for 30 days will be
(Given that the charge per kW.h of energy = ₹ 4)

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₹ 600

₹ 6,000

₹ 1,200

₹ 1,500

Answer is Right!

Answer is Wrong!

This question was previously asked in

UPSC NDA-2 – 2020

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The correct answer is (B) ₹ 6,000. First, calculate the total energy consumed. Power is 5 kW. The refrigerator works 10 hours per day for 30 days. Total hours = 10 hours/day * 30 days = 300 hours. Total energy consumed = Power * Time = 5 kW * 300 hours = 1500 kWh. The cost per kWh is ₹ 4. Total cost = 1500 kWh * ₹ 4/kWh = ₹ 6000.

Energy consumption is calculated as the product of power (in kilowatts) and time (in hours), resulting in kilowatt-hours (kWh). The cost is then found by multiplying the total energy consumed by the rate per kWh.

Electrical energy consumption is typically measured in kilowatt-hours (kWh), also known as a ‘unit’ of electricity. This is the standard unit used by electricity meters and utility companies for billing purposes.

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