The correct answer is: A. aromatic and high dipole moment.
Aromatic compounds are cyclic, planar, and conjugated molecules that have a high electron density in the ring. This high electron density results in a strong dipole moment, which is a measure of the separation of charge in a molecule.
The compound in the question is benzene, which is a classic example of an aromatic compound. Benzene is a planar molecule with a six-membered ring of carbon atoms. The carbon atoms in benzene are sp2 hybridized, which means that they have two p orbitals that are perpendicular to the plane of the ring. These p orbitals overlap to form a pi bond system that is delocalized around the entire ring. This delocalization of electrons results in a high electron density in the ring, which in turn results in a strong dipole moment.
The dipole moment of benzene is 1.5 D. This is a relatively high dipole moment, which is consistent with the high electron density in the ring.
The other options are incorrect. Option B is incorrect because benzene is not a non-aromatic compound. Option C is incorrect because benzene does not have a high dipole moment. Option D is incorrect because benzene is not an anti-aromatic compound.