The compensation for curvature on gradient for Meter Gauge is given by (where R is radius of curve.) A. $$\frac{{70}}{{\text{R}}}$$ B. $$\frac{{52.5}}{{\text{R}}}$$ C. $$\frac{{35}}{{\text{R}}}$$ D. $$\frac{{105}}{{\text{R}}}$$

The correct answer is $\frac{{52.5}}{{\text{R}}}$.

The compensation for curvature on gradient for Meter Gauge is given by the following formula:

$$\frac{{52.5}}{{\text{R}}}$$

where R is the radius of the curve.

This formula is based on the following considerations:

• The centripetal force required to keep a train moving on a curved track is proportional to the square of the speed of the train and inversely proportional to the radius of the curve.
• The force of gravity acting on a train is proportional to its mass and the acceleration due to gravity.
• The maximum speed of a train is limited by the friction between the wheels and the track.

The formula takes into account all of these factors and ensures that the train will not derail when traveling on a curved track.

The other options are

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