The correct answer is: A. Very near to inductive load.
A capacitor is a device that stores electrical energy in an electric field. It is made up of two conductive plates separated by an insulating material, called a dielectric. When a voltage is applied to the capacitor, an electric field is created between the plates. This electric field causes the charges on the plates to be separated, with positive charges on one plate and negative charges on the other plate. The amount of charge that can be stored by a capacitor depends on its capacitance, which is measured in farads.
Inductive loads are devices that store energy in a magnetic field. When an electric current flows through an inductor, a magnetic field is created around the inductor. This magnetic field can be used to store energy, and it can also be used to generate an electric current. The amount of energy that can be stored by an inductor depends on its inductance, which is measured in henrys.
When a capacitor is placed very near to an inductive load, the capacitor can help to reduce the inductive reactance of the load. This is because the capacitor creates a counter-voltage that opposes the change in current through the inductor. This counter-voltage helps to reduce the current through the inductor, which in turn reduces the inductive reactance.
The following are the brief explanations of each option:
- Option A: Very near to inductive load. This is the correct answer because the capacitor can help to reduce the inductive reactance of the load.
- Option B: Across the terminals of the inductive load. This option is incorrect because the capacitor will not be able to reduce the inductive reactance of the load if it is placed across the terminals of the load.
- Option C: Far away from the inductive load. This option is incorrect because the capacitor will not be able to reduce the inductive reactance of the load if it is placed far away from the load.
- Option D: Anywhere. This option is incorrect because the capacitor should be placed very near to the inductive load in order to reduce the inductive reactance of the load.