The correct answer is $\boxed{\text{C}}$.
The 4-point DFT of a discrete time sequence $x[n]$ is given by
$$X[k] = \sum_{n=0}^{3} x[n] e^{-j2\pi nk/N}$$
where $N$ is the number of samples in the sequence. For the sequence $x[n] = {1, 0, 2, 3}$, we have
$$X[0] = \sum_{n=0}^{3} x[n] = 1 + 0 + 2 + 3 = 6$$
$$X[1] = \sum_{n=0}^{3} x[n] e^{-j2\pi n/4} = 1 – 0 + 2e^{-j\pi} + 3e^{-j3\pi} = 2 – 2j$$
$$X[2] = \sum_{n=0}^{3} x[n] e^{-j4\pi n/4} = 1 – 0 + 2e^{-j2\pi} + 3e^{-j4\pi} = 2 + 2j$$
$$X[3] = \sum_{n=0}^{3} x[n] e^{-j6\pi n/4} = 1 – 0 + 2e^{-j3\pi} + 3e^{-j5\pi} = 0 – 2j$$
Therefore, the 4-point DFT of $x[n]$ is $\boxed{\text{C}}$.
Option A is incorrect because $X[1]$ should be $2 – 2j$, not $0 – 2j$.
Option B is incorrect because $X[2]$ should be $2 + 2j$, not $2 – 2j$.
Option D is incorrect because $X[3]$ should be $0 – 2j$, not $-1 – 3j$.